9^m+3^(3-2m)=28

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Solution for 9^m+3^(3-2m)=28 equation: 



9^m+3^(3-2m)=28

We move all terms to the left:

9^m+3^(3-2m)-(28)=0

We add all the numbers together, and all the variables

9^m+3^(-2m+3)-28=0

We move all terms containing m to the left, all other terms to the right

9^m+3^(-2m+3)=28

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